If P(A)=0.4, P(B)=0.5, P(C)=0.6, P(A∩B)=0.2 , P(B∩C)=0.3, P(C∩A)=0.25, P(A∩B∩C)=0.1 then P(A∪B∪C)=

P(A∪B∪C)=P(A)+P(B)+P(C)−P(A∩B)− P(B∩A)−P(C∩A)+P(A∩B∩C) =0.4+0.5+0.6−0.2−0.3−0.25+0.1 =1.6−0.75 =0.85

If P(A)=0.4, P(B)=0.5, P(C)=0.6, P(A∩B)=0.2 , P(B∩C)=0.3, P(C∩A)=0.25, P(A∩B∩C)=0.1 then P(A∪B∪C)=

P(A∪B∪C)=P(A)+P(B)+P(C)−P(A∩B)− P(B∩A)−P(C∩A)+P(A∩B∩C) =0.4+0.5+0.6−0.2−0.3−0.25+0.1 =1.6−0.75 =0.85

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If $P (A) = 0.4, P (B) = 0.5, P (C) = 0.6, P (A \cap B) = 0.2$ , $P (B \cap C) = 0.3, P (C \cap A) = 0.25, P (A \cap B \cap C) = 0.1$ then $P (A \cup B \cup C) =$

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$0.55$

$0.65$

$0.75$

$0.85$

answer is B.

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$P (A \cup B \cup C) = P (A) + P (B) + P (C) - P (A \cap B) -$

$P (B \cap A) - P (C \cap A) + P (A \cap B \cap C)$

$= 0.4 + 0.5 + 0.6 - 0.2 - 0.3 - 0.25 + 0.1$

$= 1.6 - 0.75 = 0.85$

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If P(A)=0.4, P(B)=0.5, P(C)=0.6, P(A∩B)=0.2 , P(B∩C)=0.3, P(C∩A)=0.25, P(A∩B∩C)=0.1 then P(A∪B∪C)=

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If $P (A) = 0.4, P (B) = 0.5, P (C) = 0.6, P (A \cap B) = 0.2$ , $P (B \cap C) = 0.3, P (C \cap A) = 0.25, P (A \cap B \cap C) = 0.1$ then $P (A \cup B \cup C) =$