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Q.

If  period of the function  f(x)=cos([n]  x)  is  2π  where  []  is G.I.F and period of another function  g(x)=p|cosx|+p2|sinx|+1000  is  π2. Then (minimum of n)+ p =

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a

2

b

1

c

3

d

4

answer is A.

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2π[n]=2π[n]=1  n=1 p=1

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