Q.

If potential energy between a proton and an electron is given |U|=ke2/2R3, where e is the charge of electron and R is the radius of atom, then radius of Bohr's orbit is given by (h = Planck's constant , k = constant)

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a

2πnke2mh2

b

ke2mh2

c

4π2ke2mn2h2

d

6π2n2ke2mh2

answer is B.

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Detailed Solution

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U=ke22R3,F=dUdR=3ke22R4

 But,  F=mv2Rmv2R=3ke22R4

 Also, mvR=nh2π

 Solve to get: R=6π2ke2mn2h2

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