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If pressure of a gas is increased by 1% when heated by1°C . It’s initial temperature must be

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100k

100°C

250K

250°C

answer is A.

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Detailed Solution

$P_{1} = P P_{2} = (\frac{101}{100}) p$

$T_{1} = T T_{2} = T + 1$

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

$\frac{P}{T} = \frac{P \frac{(101)}{100}}{T + 1}$

$T + 1 = T (\frac{101}{100})$

100(T+1)=T(101)

100T+100=101T

T=100K

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