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If PS is the median of the triangle with vertices P(2, 2), Q(6, –1) and R(7, 3) then the equation of the line passing through (1,–1) and parallel to $\bar{P S}$

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$4 x - 7 y - 11 = 0$

$2 x + 9 y + 7 = 0$

$4 x + 7 y + 3 = 0$

$2 x - 9 y - 11 = 0$

answer is B.

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Detailed Solution

S is the midpoint of QR,

$∴ S (\frac{13}{2}, 1) \Rightarrow Slope of P S = - \frac{2}{9}$

$∴$ Equation of required line is

$y + 1 = - \frac{2}{9} (x - 1) \Rightarrow∴ 2 x + 9 y + 7 = 0$

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