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If p(x) is a polynomial such that $p (x^{2} + 1) = {p (x)}^{2} + 1$ and $p (0) = 0 then p^{1} (0)$ is equal to

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Detailed Solution

$p (x^{2} + 1) = (p (x))^{2} + 1 Polynomial P (x), satisfying the given relation can be p(x)=x \Rightarrow p (x) = x, p^{1} (x) = 1 \Rightarrow p^{1} (0) = 1$

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