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Q.

If ‘q’ coulombs of charge travel through a conductor of length ‘ $l$ ’ m with a velocity of $' v^{'} m / s$ , the current flowing through the conductor is:

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a

\frac{ql}{v}

b

\frac{q^{2} v}{l}

c

\frac{qv}{l}

d

qlv

answer is C.

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Detailed Solution

If ‘q’ coulombs of charge travel through a conductor of length ‘l’ m with a velocity of

' v^{'} m / s

, the current flowing through the conductor is

\frac{qv}{l}

.
Electric charge is the intrinsic property of the certain fundamental particles due to which they can produce electric and magnetic effects. And electric current is defined as the quantity of charge flowing through a given point of conductor in one second.
So, electric current,

i = \frac{q}{t}

Here, length of conductor is

' l^{'} m

and velocity is

' v^{'} m / s

.
We know that length is the product of velocity and time, so,

l = v \times t

\Rightarrow t = \frac{l}{v}

So,

i = \frac{qv}{l}

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