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Q.

If “R” is radius of the earth, at what height above the earth's surface the acceleration due to gravity is 1 % of its value on the surface?

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a

10 R

b

3 R

c

11 R

d

9 R

answer is B.

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Detailed Solution

$g^{1} = \frac{g R^{2}}{{(R + h)}^{2}}$

$1 = \frac{100 R^{2}}{{(R + h)}^{2}}$

$h = 9 R$

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