If R is the circum radius and $\mathrm{r}, {\mathrm{r}}_1, {\mathrm{r}}_2, {\mathrm{r}}_3$ are inradius and ex-radii of the triangle then the roots of the equation ${\mathrm{x}}^3–(4\mathrm{R}+\mathrm{r}){\mathrm{x}}^2+{\mathrm{s}}^2\mathrm{x}–\mathrm{r}{\mathrm{s}}^2=0$ are