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Q.

If R is the range of a projectile on a horizontal plane and h its maximum height, the maximum horizontal range with the same velocity of Projection is:

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a

2h+R28R

b

2R+h28R

c

2h

d

R2 /8h

answer is D.

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Detailed Solution

R=2u2sinθcosθ2gand h=u2sin2θ2g
⇒R2=4u4sinθ2cosθ2g2
R28h=u2g−2h⇒maximum range = u2g=R28h+2h

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