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If radius of ground state of H-atom (according to Bohr's model) is 'R' then radius of 3rd energy state of ${Li}^{+ 2}$ is:

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R/2

answer is B.

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Detailed Solution

Radius of ground state;

$R = a_{0} \times \frac{1^{2}}{1};$

Radius of 3rd energy state;

$r = a_{0} \times \frac{3^{2}}{3} = 3 R$

This radius is 3 times the radius of ground state.

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