If R_H is Rydberg constant, then energy of electron in the ground state hydrogen atom is given by

${\mathrm{E}}_{\mathrm{n}}=\frac{-2{\mathrm{\pi }}^2{\mathrm{z}}^2{\mathrm{me}}^4}{{\mathrm{n}}^2{\mathrm{h}}^2}$

for H-atom Z = 1

Ground state n = 1

$\mathrm{E}=\frac{-2{\mathrm{\pi }}^2{\mathrm{me}}^4}{{\mathrm{h}}^2}$

${\mathrm{R}}_{\mathrm{H}}=\frac{2{\mathrm{\pi }}^2{\mathrm{me}}^4}{{\mathrm{Ch}}^3}$

${\mathrm{R}}_{\mathrm{H}}=\left(\frac{2{\mathrm{\pi }}^2{\mathrm{me}}^4}{{\mathrm{h}}^2}\right)\left(\frac{1}{\mathrm{Ch}}\right)$

${\mathrm{hcR}}_{\mathrm{H}}=\frac{2{\mathrm{\pi }}^2{\mathrm{me}}^4}{{\mathrm{h}}^2}$

R_HhC = - E

E= -R_HhC