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If RMS velocity of Ozone at $- 73^{0} C$ is $1.2 {ms}^{- 1},$ the RMS velocity at $527^{0} C$

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$0.6 {ms}^{- 1}$

$2.4 m / \sec$

$4 {ms}^{- 1}$

$0.8 {ms}^{- 1}$

answer is C.

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Detailed Solution

$\frac{C_{1}}{C_{2}} = \sqrt{\frac{T_{1}}{T_{2}}} \frac{1.2}{C_{2}} = \sqrt{\frac{200}{800}} = \sqrt{\frac{1}{4}} = \frac{1}{2} C_{2} = 2 \times 1.2 = 2.4 m / \sec$

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