If  roots of the equation $l{x}^2+mx+n=0$  are $\left(2\alpha \right)$  and  $(\alpha +\beta )$ , roots of the equation $p{x}^2+qx+r=0$  are  $\left(2\beta \right)$  and  $(\alpha +\beta )$  and  $D_1$  and  $D_2$  are the respective discriminants, then  $\frac{D_1}{D_2}$ is equal to (where  $\alpha \ne \beta$ )