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Q.

If roots of x 2 (a3)x+a=0   are such that at least one root is greaterthan 2, then  a belongs to

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a

(9,10)  

b

[9,)  

c

[7,)  

d

[7,9]    

answer is B.

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Detailed Solution

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  x 2 (a3)x+a=0  
D= (a3) 2 4a=(a1)(a9) 

 Case (i) when both roots are >2  
D0,f(2)>0  , sum of roots >4
(a1)(a9)0,42(a3)+a>0,a3>4a1a9,a<10,a>7 
We have a[9,10)(1)  
Case (ii) when only one root is >2 and other is 2  
f(2)0 and D>0  
a10 and a<1,a>9 We have a[10,)(2)  

a[9,10)[10,)a[9,)
From (1) &(2) a[9,)    

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