If S is the circumcentre, O is the orthocentre of ΔABC, then $SA + SB + SC =$

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2SO

2OS

answer is A.

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Detailed Solution

Let D be the midpoint of BC.
Vector BD = vector DC
=> vector DB + vector DC = vector o
Also, 2SD = AO
2 vector SD = vector AO
vector{SA + SB + SC} = vector{SA + (SD + DB) + (SD + DC)}
= vector{SA + 2SD + (DB + DC)}
= vector{SA + AO + o}
= vector SO
So, Option 1 is correct.

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