Q.

If  α satisfies the inequation  x2x2>0, then a value exists for

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a

sin1α

b

None of these

c

sec1α

d

cos1α

answer is B.

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Detailed Solution

x2x2>0

(x2)(x+1)>0

x<1​ orx>2, using sign scheme

We know that  sin1x is defined for  |x|1,cos1x is define for

|x|1andsec1x |x|1,i.e.,x1orx1

Hence, (B) is the correct answer

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