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Q.

If $\sin A = \sin B$ and $\cos A = \cos B$ , then $A =$

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a

2 n π + B, n \in z

b

n π + B, n \in z

c

n π + {(- 1)}^{n} B, n \in z

d

2 n π - B, n \in z

answer is A.

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Detailed Solution

\sin A = \sin B, \cos A = \cos B

$\tan A = \tan B$

$A = 2 n π + B$

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