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Q.

If sinh12α=2cosh1β then 

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a

α2=β2

b

α2+β2=β4

c

α2+β2=4

d

α2+β2=α4

answer is B.

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Detailed Solution

sinhx=2α,  β=coshx2
sinhx2=αβ
Now cosh2x2sinh2x2=1
  α2+β2=β4

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