If $\tan 35°+\cot 37°+\tan 325°=x\tan 53°+\tan 127°$ then $x=$

$\tan 35+\cot 37+\tan \left(360-35\right)=x\tan 53+\tan \left(90+37\right)$

$\tan 35+\cot 37-\tan 35=x\tan 53-\cot 37$

$2\cot 37=x\tan 53$

$2\cot \left(90-53\right)=x\tan 53$

$2\tan 53=x\tan 53$

$\boxed{x=2}$