Q.

If  tan5θ=cot2θ then the principal value of θ =

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a

θ=π7

b

θ=π14

c

θ=π14

d

θ=π7

answer is A.

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Detailed Solution

tan5θ=cot2θ=tan(π22θ) 5θ=nπ+π22θ7θ=nπ+π2

θ=nπ7+π14, where  nZ, but n3,10,17,. 
Where tan 5θ is not defined

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