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Q.

If the weight of 5.6 lit of gas at NTP is $11 g,$ the gas may be (at.wt of $P = 31, N = 14, O = 16$ and $C l = 35.5$ )

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a

$N_{2} O$

b

$N O$

c

$C O C l_{2}$

d

$P H_{3}$

answer is D.

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Detailed Solution

$M = \frac{W R T}{P V}$

$= \frac{11 \times \frac{22.4}{273} \times 273}{1 \times 5.6}$

$= 44$

$∴$ The gas is $N_{2} O$

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If the weight of 5.6 lit of gas at NTP is 11 g, the gas may be (at.wt of P=31, N=14, O=16 and Cl=35.5 )