Q.

If the activation energy for the forward reaction is 150 kJ mol-1 and that of the reverse reaction is 260 kJ mol-1. What is the enthalpy change for the reaction
 

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a

-110 kJ mol-1
 

b

-410 kJ mol-1

c

410 kJ mol-1
 

d

110 kJ mol-1

answer is B.

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Detailed Solution

Enthalpy change for a reversible reaction,

 ΔH=Ea(forward)Ea(backward) ΔH=150260=110kJ mol1

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