If the angle between electric current and magnetic field (B) is θ, then magnetic force (F) is

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$F = qvB \sin θ$

$F = qvB \tan θ$

$F = qvB \cos θ$

$F = qvB \cot θ$

answer is B.

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Detailed Solution

Explanation:

The magnetic force (F) on a charged particle moving in a magnetic field is determined by the Lorentz Force Law, which states:

F = q × v × B × sinθ

Where:

q: Charge of the particle
v: Velocity of the charged particle
B: Magnetic field strength
θ: Angle between the velocity (v) of the charged particle and the magnetic field (B)

Key Points:

The force is maximum (F_max = qvB) when θ = 90°, as sin 90° = 1.
The force is zero (F = 0) when θ = 0° or θ = 180°, as sin 0° = 0 and sin 180° = 0.
The magnitude of the force depends on the sine of the angle between the velocity and the magnetic field, making the correct formula: F=qvBsin⁡θ

Final Answer

F = qvB sinθ

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