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If the angle of inclination of the inclined plane is $\sin^{- 1} (\frac{1}{2})$ when the body just starts sliding find the angle of repose and coefficient of static friction between the body and the inclined plane.

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$45^{\circ}, \frac{1}{\sqrt{3}}$

$30^{0}, \frac{1}{2}$

$30^{0}, \frac{1}{\sqrt{3}}$

$60^{\circ}, \frac{2}{\sqrt{3}}$

answer is C.

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Detailed Solution

Given, $\sin θ = \frac{1}{2}$

$\Rightarrow θ = 30^{0}$

Just sliding condition,

$m g \sin θ = μ m g \cos θ$

$\Rightarrow μ = \tan θ = \frac{1}{\sqrt{3}}$

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