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If the angles of a triangle are in the ratio 3 : 4 : 5, then the ratio of the corresponding sides is

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$2 : \sqrt{2} : 3$

$2 : \sqrt{6} : \sqrt{3} + 1$

$\sqrt{3} : 2 : \sqrt{5}$

$\sqrt{2} : \sqrt{6} : \sqrt{3} + 1$

answer is B.

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Detailed Solution

The angles are 45°, 60°, 75°

$∴$ Ratio of sides is

sin 45° : sin 60° : sin 75°

$\begin{aligned} = \frac{1}{\sqrt{2}} : \frac{\sqrt{3}}{2} : \frac{\sqrt{3} + 1}{2 \sqrt{2}} \\ i.e., 2 : \sqrt{6} : \sqrt{3} + 1 \end{aligned}$

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