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If the Arithmetic means of two numbers is 10, and their product is 91, then the numbers are

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13, 7

14, 6

15, 5

12, 8

answer is A.

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Detailed Solution

$\frac{a + b}{2} = 10 \Rightarrow a + b = 20$

$a b = 91$

${(a - b)}^{2} = {(a + b)}^{2} - 4 a b$

$= 400 - 4 \times 91$

$= 400 - 364$

$= 36$

$a = 13$ ; $b = 7$

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