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If the atmospheric pressure is 76cm of Hg at what depth of water in a lake the pressure will becomes 2 atmospheres nearly.

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932 cm

1033 cm

862 cm

982 cm

answer is D.

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Detailed Solution

Given:

P₀=76 cm of Hg

P₀=hρg=76×136×980 dynes

P=P₀+hρg

2P₀=P₀+hρg

P₀=hρg

76×13.6×980=h×1×980

h=76×13.6=1033 cm

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