If the atomic number of an element is 26. The magnetic moment (in BM) exhibited by its ion in its +2 oxidation state will be

An element's electronic configuration is d⁶ with 4 unpaired electrons if its ion is in the +2 oxidation state and it has an atomic number of 26.

The formula for the magnetic moment$\sqrt{\mathrm{n}(\mathrm{n}+2)}$

Where 'n' = no. of unpaired electrons.

Therefore the Magnetic moment is $\sqrt{4(4+2)} = 4.9 \mathrm{\mu B}(\mathrm{Bohr} \mathrm{magneton})$