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Q.

If the binding energy of the ground state electron in a hydrogen atom is 13.6 eV, then the energy required to remove the electron from the second excited state of Li2+ will be; 1 x eV 10-1. The value of x is _____

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answer is 136.

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Detailed Solution

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Energy required to remove electron E=13.62n2eV
In H-atom ⇒z=1, ground state n =1

For Li2+⇒Z=3

2nd excited state , n = 3
E1=13.6×329=13.6eVx×10−1=13.6x=136


 

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