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Q.

If the binding energy per nucleon in Li7 and He4 nuclei are respectively 5.60 MeV and 7.06 MeV then energy of reaction Li7+p22He4 is

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a

2.4 MeV

b

8.4 MeV

c

17.3 MeV

d

19.6 MeV

answer is D.

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Detailed Solution

Energy of reaction = 2(4) (7.06) – 7(5.60) = 17.28 MeV

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