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Q.

If the binding energy per nucleon in Li7 and He4 nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction Li7+p2 2He4 is

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a

2.4 MeV

b

8.4 MeV

c

17.3 MeV

d

19.6 MeV

answer is D.

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Detailed Solution

 B.E. of Li7=39.20MeV and He4=28.24MeV  Hence binding energy of 2He4=56.48MeV  Energy of reaction =56.4839.20=17.28MeV.

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