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If the blocks are moving as shown in the figure the relation between $a_{1}, a_{2} and a_{3}$ will be

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$2 a_{1} + 2 a_{2} + a_{3} = 0$

$2 a_{1} - 2 a_{2} + a_{3} = 0$

$2 a_{1} - 2 a_{2} - a_{3} = 0$

$2 a_{2} - 2 a_{1} + a_{3} = 0$

answer is C.

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Detailed Solution

From pulley (3)

$a_{2} = \frac{2 a_{1} - a_{3}}{2}$

$2 a_{2} = 2 a_{1} - a_{3}$

$2 a_{1} - 2 a_{2} - a_{3} = 0$

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