If the boiling point of ${\mathrm{H}}_2\mathrm{O}$ is 373 K, the boiling point of ${\mathrm{H}}_2\mathrm{S}$ will be : 

At room temperature water is liquid and has high Boiling point 373K due to inter molecular hydrogen bonding where as ${\mathrm{H}}_2\mathrm{S}$  is gas it has no hydrogen bonding. Hence is less than 300K. [BP if ${\mathrm{H}}_2\mathrm{S}$ is -60ºC]

$\begin{array}{l}\text{ b.p. of }{\mathrm{H}}_2 \mathrm{S}\le {\mathrm{H}}_2\mathrm{O}\\ \mathrm{bp}\left({\mathrm{H}}_2\mathrm{O}\right)=373 \mathrm{K}\\ \mathrm{bp}\left({\mathrm{H}}_2 \mathrm{S}\right)=213 \mathrm{K}\end{array}$