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Q.

If the bond energies of H-H,Br-Br and H-Br are 433,192 and 364 kJ mol-1 respectively, then ΔH0 for the reaction H2(g)+Br2(g)2HBr

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a

+261 kJ

b

+103 kJ

c

-103 kJ

d

-261 kJ

answer is D.

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Detailed Solution

 The bond between hydrogen and bromine molecules is broken and bond formation takes place between hydrogen and bromine atoms to form HBr

One mole of hydrogen and bromine reacts to give 2 moles of HBr

 ΔH0=ΔHH-H+ΔHBr-Br-ΔHH-Br

 ΔH0=433+192-2(364)

 ΔH0=625-728=-103

Hence correct answer will be (D).

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If the bond energies of H-H,Br-Br and H-Br are 433,192 and 364 kJ mol-1 respectively, then ΔH0 for the reaction H2(g)+Br2(g)⟶2HBr