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Q.

 If the bond enthalpy of O2, N2 and H2 are 498 kJ mol-1, 946 kJ mol-1 and 435.8 kJ mol-1respectively. Choose
the correct order of decreasing bond strength.

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a

H2>N2>O2

b

O2>H2>N2

c

N2>O2>H2

d

H2>O2>N2

answer is B.

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Detailed Solution

Larger the bond dissociation enthalpy stronger will be the bond in the molecule so,

  N2      >    O2     >   H2

946kJ       498kJ      435.8kJ    

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