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If the breadth of Rectangle 1 and Rectangle 2 is 30 cm and 45 cm respectively. The area of rectangle 1 is $900 {cm}^{2}$ and area of the rectangle 2 is $1350 {cm}^{2}$ . Then compare the lengths of rectangle

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length of rectangle 1 is greater than rectangle 2

length of rectangle 2 is greater than rectangle 1

Both are same

none of these

answer is C.

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Detailed Solution

Given,
Breadth of Rectangle 1 = 30 cm
Breadth of Rectangle 2 = 45 cm
Area of a rectangle

1 = 900 {cm}^{2}

Now, the area of rectangle

A_{1} = Length (l_{1}) \times breadth (b_{1})

900 {cm}^{2} = l_{1} \times 30

l = \frac{900}{30}

l_{1} = 30 cm

Area of rectangle

2,

A_{2} = Length (l_{2}) \times breadth (b_{2})

1350 {cm}^{2} = l_{2} \times 45

l_{2} = 1350 {cm}^{2}

l_{2} = \frac{1350}{45} = 30 cm

Thus, lengths of the rectangles

l_{1} = l_{2}

.
Correct option is 3.

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