If the centroid and a vertex of an equilateral triangle are (2, 3) and (4, 3) respectively, then the other two vertices of the triangle are

G being the centroid, divides AD in the ratio 2 : 1.

Since AG = 2,$\therefore$ GD = 1,
$\therefore$ Coordinates of D, using section formula, are D(1, 3).
Now AD = 1 + 2 = 3, $\therefore \tan {60}^0=\frac{3}{BD}\Rightarrow BD=\sqrt{3}$

$\therefore B\equiv \left(1,3+\sqrt{3}\right) and C\equiv \left(1,3-\sqrt{3}\right)$