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Q.

If the centroid of the tetrahedron ABCD is  G(0,1,52) and three vertices are  A(2,3,4),B(3,4,2),C(2,5,1)  then the distance of centroid G from fourth vertex D is

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a

372

b

732

c

734

d

374

answer is C.

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Detailed Solution

G=(0,1,52)   A=(2,3,4)B=(3,4,2)   C=(2,5,1)  D=4GABC =(3,2,3)   GD=732

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