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Q.

If the CFSE of TiH2O63+ is 96.0kJ/mol, this complex will absorb maximum at wavelength _____nm. (nearest integer)
Assume Planck’s constant (h)=6.4×1034Js, speed of light (c)=3.0×108m/s and 
Avogadro’s Constant NA=6×1023/mol.

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answer is 480.

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Detailed Solution

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 CFSE =0.4Δ96.0kJ/mol=0.4ΔΔ=96×1030.4J/molΔ=96×1030.4×6×1023J/moleculeλ=hcΔ=6.4×1034×3×8×0.4×6×102396×103=0.48×106m=480nm

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