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If the change in the value of g at a height h above the surface of the earth is same as at depth ‘x’ below the surface of the earth, then (h<<R)

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x = 2h

x = h

x = h²

x = h/2

answer is B.

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Detailed Solution

$g_{h} = g (1 - \frac{2 h}{R}) a n d g_{d} = g (1 - \frac{x}{R})$

$c h a n g e = \frac{2 g h}{R} = \frac{g x}{R} \Rightarrow x = 2 h$

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