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Q.

If the charge on an object is doubled then electric field becomes

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a

Unchanged

b

Half

c

Double

d

Thrice

answer is B.

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Detailed Solution

As $E = \frac{1}{4 {πε}_{0}} \frac{q}{r^{2}}$

If $q^{'} = 2 q,$ then $E' = \frac{1}{4 {πε}_{0}} \frac{2 q}{r^{2}}$ or $E^{'} = 2 E$

So, electric field is doubled.

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