Q.

If the circle x2+y2= r2 intersects the hyperbola xy=c2 in four points (xi, yi) for i = 1,2,3 and 4 then y1+y2+y3+y4= 

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a

0

b

c

c

a

d

c4

answer is A.

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Detailed Solution

Given circle x2+y2=r2        and hyperbola xy=c2 x=c2y       Now P.I of  &  is c2y2+y2=r2 c4y2+y2=r2 y4-r2y2+c4=0 It has four roots let it be y1, y2, y3, y4 Now y1+y2+y3+y4=0

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