If the coefficients of x and x² in (1+x)^p(1-x)^q are 4 and -5 respectively, then 2p+3q is equal to

$$\begin{gathered} (\mathrm{x}+1{)}^{\mathrm{p}}(1-\mathrm{x}{)}^{\mathrm{q}} \\ \text{ Coefficient of }\mathrm{x}{=}^{\mathrm{p}}{\mathrm{C}}_0\cdot \left({-}^{\mathrm{q}}{\mathrm{C}}_1\right){+}^{\mathrm{p}}{\mathrm{C}}_1{\cdot }^{\mathrm{q}}{\mathrm{C}}_0 \\ \boxed{4=-\mathrm{q}+\mathrm{p}} \\ \text{ Coefficient of }{\mathrm{x}}^2{=}^{\mathrm{p}}{\mathrm{C}}_0^{\mathrm{q}}{\mathrm{C}}_2{+}^{\mathrm{p}}{\mathrm{C}}_2^{\mathrm{q}}{\mathrm{C}}_0{-}^{\mathrm{p}}{\mathrm{C}}_1^{\mathrm{q}}{\mathrm{C}}_1 \\ \begin{array}{l}-5=\frac{\mathrm{q}(\mathrm{q}-1)}{2}+\frac{\mathrm{p}(\mathrm{p}-1)}{2}-\mathrm{pq}\\ -10={\mathrm{q}}^2-\mathrm{q}+{\mathrm{p}}^2-\mathrm{p}-2\mathrm{pq}\\ -10=\left({\mathrm{p}}^2+{\mathrm{q}}^2-2\mathrm{pq}\right)-(\mathrm{p}+\mathrm{q})\\ -10=(\mathrm{p}-\mathrm{q}{)}^2-(\mathrm{p}+\mathrm{q})\\ -10=4^2-(\mathrm{p}+\mathrm{q})\\ \mathrm{p}+\mathrm{q}=16+10=26\\ \Rightarrow 2\mathrm{p}=26+4\\ \Rightarrow \mathrm{p}=15\\ \Rightarrow \mathrm{q}=11\\ 2\mathrm{p}+3\mathrm{q}=2\left(15\right)+3\left(11\right)\\ =30+33\\ =63\end{array} \end{gathered}$$