If the concentration of glucose (C₆H₁₂O₆) in blood is 0.9 g L^-1, what will be the molarity of glucose in blood?

Molarity $\mathrm{=}\frac{{\mathrm{W}}_{\mathrm{B}}( \mathrm{in} \mathrm{g})}{{\mathrm{M}}_{\mathrm{B}}\left( \mathrm{in} \mathrm{g}{\mathrm{mol}}^{-1}\right)\times \mathrm{Volume} \mathrm{of} \mathrm{solution}(\mathrm{in} \mathrm{L}) }$

$\mathrm{=}\frac{ \mathrm{Conc}. \left( \mathrm{in} {\mathrm{gL}}^{-1}\right)}{{\mathrm{M}}_{\mathrm{B}}\left( \mathrm{in} \mathrm{g}{\mathrm{mol}}^{-1}\right)}=\frac{0.9}{180}=0.005\mathrm{M}$
$\left(\because \mathrm{Molar} \mathrm{mass} \mathrm{of} {\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6=180 \mathrm{g} {\mathrm{mol}}^{-}\right)$