If the concentration of glucose (${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6$) in blood is 0.9 g ${\mathrm{L}}^{-1}$, what will be the molarity of glucose in blood?

$1\text{ mole of glucose }\left({\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\right)=12\times 6+12\times 1+6\times 16$

                                               = 72+ 12+ 96= 180 g

$\text{ Molarity of glucose }=\frac{0.9}{180} \mathrm{mol}/\mathrm{L}=0.005\mathrm{M}$