Q.

If the concentration of glucose C6H12O6 in blood is 0.72  g L-1, the molarity of glucose in blood is   _______ ×10-3M. [Given : Atomic mass of C=12,H=1,O=16u]

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answer is 4.

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Detailed Solution

[ Glucose ]=C(gm/)M(gm/mol)


=0.72180=4×10-3M

Hence, the correct answer is 4×10-3M.

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