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Q.

If the concentration of water vapour in the air is 1% and the total atmospheric pressure equals 1 atm then the partial pressure of water vapour is:

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a

1 mm Hg

b

100 atm

c

7.6 mm Hg

d

0. 1 atm

answer is C.

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Detailed Solution

$P_{H_{2} O} = P_{T} \times molefraction of H_{2} O P_{H_{2} O}^{'} = P_{Air} \times \frac{1}{100} = 760 \times \frac{1}{100} = 7 .6 mm of Hg$

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