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Q.

If the constant term in the binomial expansion of(x21x)n , nN is 15 then the value of n is equal to _____.

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Detailed Solution

Tr+1 in (x21x)n is nCr(x2)nr(1)rxr 

                            =  nCr(x)2n3r(1)r

Constant term =  nCr(1)r ,if2n=3r i.e coefficient off x=0

Hence nC2n/3(1) 2n/3=15

 6C4n=6  

 

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