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Q.

If the coordinates of ends of a focal chord of the parabola y2 = 4ax are (x1,y1) and (x2,y2). Then P.T x1x2=a2,y1y2=4a2

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Detailed Solution

 Let x1,y1=at12,2at1
x2,y2=at22,2at2 are end of focal chord then 

 we know that t1t2=1
x1x2=a2t1t22=a2(1)2=a2
Question Image
y1y2=4a2t1t2=4a2(1)=4a2

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